Gratuitous Pictures of Yourself 2.0

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AngelicSongx
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Re: Gratuitous pictures of yourself 2

Post by AngelicSongx »

I was wondering if that would pop into this thread. But yep that's me too.
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Nachalnik
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Re: Gratuitous pictures of yourself 2

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Re: Gratuitous pictures of yourself 2

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Re: Gratuitous pictures of yourself 2

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musicandilikeit
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Re: Gratuitous pictures of yourself 2

Post by musicandilikeit »

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D-vid
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Re: Gratuitous pictures of yourself 2

Post by D-vid »

x = 1/9 * 4th root of 3
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Omnithea
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Re: Gratuitous pictures of yourself 2

Post by Omnithea »

NEEEEEEEEEEEEEEEEEEEEEEERRRRRRRRRRRRRRRRRRRRRRRRRRRDDDDDDDDDDDDDDD!!!!!!!!!!!!!
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Stranaton
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Re: Gratuitous pictures of yourself 2

Post by Stranaton »

Omnithea wrote:NEEEEEEEEEEEEEEEEEEEEEEERRRRRRRRRRRRRRRRRRRRRRRRRRRDDDDDDDDDDDDDDD!!!!!!!!!!!!!
no, he's German :awesomeface:
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ZenithOfChaos
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Re: Gratuitous pictures of yourself 2

Post by ZenithOfChaos »

Actually, x can be both positive and negative, since the absolute value is apparent in squares.
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Sollix
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Re: Gratuitous pictures of yourself 2

Post by Sollix »

Omnithea wrote:NEEEEEEEEEEEEEEEEEEEEEEERRRRRRRRRRRRRRRRRRRRRRRRRRRDDDDDDDDDDDDDDD!!!!!!!!!!!!!
:V zen you walked right into that one
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ZenithOfChaos
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Re: Gratuitous pictures of yourself 2

Post by ZenithOfChaos »

I'm not wearing my glasses. I can't see a thing without my glasses.
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D-vid
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Re: Gratuitous pictures of yourself 2

Post by D-vid »

x = (3x)² / 4th root of 3 // expand (3x)²
x = 9 x² / 4th root of 3 // * 4th root of 3
4th root of 3 * x = 9 x²
// now were x negative, then you'd have a negative value on the left and a positive on the right, so the negative x is false. /x

4th root of 3 = 9 x // * 1/9

4th root of 3 * 1/9 = x
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ZenithOfChaos
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Re: Gratuitous pictures of yourself 2

Post by ZenithOfChaos »

HAHAHA! I knew I was wrong from the very beginning. You've fallen into my trap D-vid. Now, I can call you a DOUBLE NERD. Seriously, I knew I was wrong... I just wanted to see someone call me on it. Not sure why. I may be drunk.
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Lolita wrote:yesssss my transformation into a slut is complete

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Sollix
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Re: Gratuitous pictures of yourself 2

Post by Sollix »

D-vid wrote:x = (3x)² / 4th root of 3 // expand (3x)²
x = 9 x² / 4th root of 3 // * 4th root of 3
4th root of 3 * x = 9 x²
// now were x negative, then you'd have a negative value on the left and a positive on the right, so the negative x is false. /x

4th root of 3 = 9 x // * 1/9

4th root of 3 * 1/9 = x

Staaahhhhhp. My brains gonna explode
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ZenithOfChaos
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Re: Gratuitous pictures of yourself 2

Post by ZenithOfChaos »

It's really not a complicated problem. The 4th root of three just looks really intimidating.
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Lolita wrote:yesssss my transformation into a slut is complete

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