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Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 8:16 am
by Lambeth
If anyone needs help on american or canadian history I can totally be that guy. World history/world culture stuff too.

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 9:31 am
by Myk
how do i find the factors to polynomials again

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 9:36 am
by Reyo
I can help with biolological stuff.

No seriously.

Also on the off chance that anyone has Military Science material they need help on I'm fairly proficient at it. There's also medium level proficiency with Math, Psychology, and Chemistry (though do try to resist the urge to ask Chemistry questions).
Clyve wrote: Biology (HOT daisies I LOVE ME SOME LIFE SCIENCES.)
SHITYEAH!
*high five*
Myk wrote:how do i find the factors to polynomials again
2 questions:

1. Are you going from 2 or more parenthesis enclosed subsets to one equation, or vise versa?
2. How ridiculous are these polynomials you need help with?

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 10:20 am
by D-vid
maths and programming in Delphi and java. Also German.
Come at me.

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 2:45 pm
by Myk
finding the factor of a polynomial. from 10x^2 - 2x - 1 and finding the factor of that and whatnot. simple

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 3:49 pm
by Sollix
I could use help in English and Essay writing specifically MLA.

I can offer help in History (European) and music!
dvid wrote: German
I am all over you.

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 5:03 pm
by Bexton
It is these kind of threads that make me realize that I have no marketable skills.

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 5:05 pm
by Syobon
Myk wrote:finding the factor of a polynomial. from 10x^2 - 2x - 1 and finding the factor of that and whatnot. simple
General form of polynomials: ax²+bx+c=0
sqrt(arg)= square root of argumenent (arg)
First calculate the determinant with D=b²-4ac
If D>0 then your factors/solutions are
x1=(-b+sqrt(D))/(2a)
and
x2=(-b-sqrt(D))/(2a)
If D=0, then there's only one solution given by
x=-b/2ac
If D<0 then your factors/solutions are complex and:
x1=(-b+sqrt(D)i)/(2a)
and
x2=(-b-sqrt(D)i)/(2a)
Fuuu, and now I realise I actually did this wrong during my differential equations exam -.-

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 6:54 pm
by D-vid
alternatively, divide by a. then it's (b is the result of b/a, c is c/a) b/2 +- sqrt((b/2)²-c)
if the number inside the sqrt is negative there is no solution, else x1 is if you use + , x2 if you use - at the +-
Crisp wrote:I am all over you.
Sure, just don't be a lazy butt and take your learning stuffs with you and actually practice at home for at least 15 minutes daily.

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 6:55 pm
by Doormaster
Advice on papers: Don't try and do it all at once. If you've got time before it's due, just do a bit each day. 250-500 words a day adds up pretty quick

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 7:00 pm
by Sollix
D-vid wrote:alternatively, divide by a. then it's (b is the result of b/a, c is c/a) b/2 +- sqrt((b/2)²-c)
if the number inside the sqrt is negative there is no solution, else x1 is if you use + , x2 if you use - at the +-
Crisp wrote:I am all over you.
Sure, just don't be a lazy butt and take your learning stuffs with you and actually practice at home for at least 15 minutes daily.

Yes Mom. >:T

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 7:01 pm
by D-vid
I can't teach you if you're not willing to learn. [/teacher]

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 7:06 pm
by Sollix
>:T Fine. FINE.

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 7:23 pm
by hotb
Myk wrote:finding the factor of a polynomial. from 10x^2 - 2x - 1 and finding the factor of that and whatnot. simple
pure text is a bit of an eyesore so here's the quadratic equation as an image
Image
Like Syobon said, the general form of quadratic polynomials is ax²+bx+c=0 so just whack the corresponding numbers into the equation. You will get two answers unless the determinant (the stuff under the root) equals zero in which case there is only one.

If the stuff under the root equals is negative then there is no root (the graph of the function does not touch or cross the x-axis) /it has a complex root but I'm guessing you don't need to deal with that

Image

By the way I can also help with physics but I have no idea what is on the american syllabus so idk lol

Re: Study Buddies (AKA NOW LET US ALL NOT FAIL CLASSES AND S

Posted: Thu Jan 19, 2012 7:52 pm
by Fatehehhhh
Kamak wrote:Also, suddenly I almost feel like starting a book club on AZ, but that's probably a terrible idea.
The book is "The Giver". The first response is asking why there are no dicks.
but yeah I could help in English but I'm not available a lot. If you can make my crazy-unorthodox schedule work for you, I'm more than pop flyin'.